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A student rolled 2 dice. What is the probability that the first die landed on a number less than 3 and the second die

landed on a number greater than 3?
0.500
0.167
0.111
0.083

User GuiRitter
by
5.9k points

2 Answers

4 votes

0.167

Explanation:

I got it right

User Natsathorn
by
6.4k points
2 votes

Answer:

B) 0.167

Explanation:

The student has 2 dice. We are assuming that both of those dice are limited at 6 (a number cube).

The first die needs to land on a number less than 3 (and it does not include 3). This means that there are two numbers that can meet the requirements, 1 & 2, which makes the chance 2/6, or 1/3.

The second die needs to land on a number greater than 3 (and it does not include 3). This means that there are 3 numbers that can meet the requirements, 4, 5, & 6, which makes the chances 3/6 or 1/2.

Multiply the two fractions together:

1/3 x 1/2 = 1/6

Divide, change to decimal:

1/6 = 0.167 (rounded)

B) 0.167 is your answer.

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User IndoKnight
by
6.3k points