Answer:
One-fourth of a number is three more than one-seventh of same number.The required number is 28.
Solution:
Let’s assume require number be x
One fourth of a number =
![(1)/(4) * \text { the number }](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wggp7mq5z4ad1qfio4fk3buwaergwuiczt.png)
![=(1)/(4) x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vmsjm1a2yc8rgxupdph17cn6zfd1gd2yuu.png)
![=(x)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gpiwmgfeuc8wol8l79zmp9vfog2ccar9aq.png)
One seventh of a number =
![(1)/(7) * \text { the number }](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v1ard4gj4u510wibh69dkzavfxex8ilp6f.png)
![=(1)/(7) x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b2aafl1m62lphgwepsbba4stz1tkzm7tjh.png)
![=(x)/(7)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dphto28x9bdasaey0x0dgy8g8zqux1n9m6.png)
Given that one fourth of a number is 3 more than one seventh of a number
So in other words if we add 3 to one seventh of a number, we will get one fourth of a number.
![(x)/(7)+3=(x)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wnl7y2zyh4xgyp1rb7dxf2ovpheyocq876.png)
![(x+21)/(7)=(x)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/noz225qb3lcuxkpq1wxypnewoo3vacv7dq.png)
4(x+21) = 7x
4x + 84 = 7x
84 = 7x – 4x
3x = 84
x = 28
Hence required number is 28.