Question

liquid water at 50 degrees celsius and 1 bar is superheated to produce steam, at 350 degrees celsius and 5 bar. What is the change in enthalpy (kJ/kg) for this process? report answer using 5 signifcant figures and units of kJ/kg.

Answer 1

Δ h = 2958.9 kJ/kg

Step-by-step explanation:

initial state

T₁ = 50⁰C

P₁ = 1 bar

from steam table , Enthalpy at 50⁰C and 1 bar

h₁ = 208.785 kJ/kg

final state

T₂ = 350⁰C

P₂ = 5 bar

from steam table , Enthalpy at 350⁰C and 5 bar

h₂ = 3167.75 kJ/kg

change in entalpy for the process

Δ h = h₂ - h₁

= 3167.75 - 208.785

Δ h = 2958.965 kJ/kg

the change in enthalpy is equal to Δ h = 2958.9 kJ/kg