Question

What is the molarity of an intravenous glucose solution prepared from 108 g of glucose in 2.0 L of solution? 0.018 mol/L 0.30 mol/L 0.60 mol/L 2.2 x 102 mol/L

Answer 1

The molarity of the intravenous glucose solution prepared from 108 g of glucose in 2.0 L of solution is 0.30 mol/L.

Step-by-step explanation:

To find the molarity of the intravenous glucose solution, we need to calculate the number of moles of glucose and then divide it by the volume of the solution.

The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol.

First, we convert the mass of glucose to moles by dividing 108 g by the molar mass:
108 g / (180.16 g/mol) = 0.5998 mol

Then, we divide the number of moles by the volume of the solution (2.0 L):
0.5998 mol / 2.0 L = 0.30 mol/L

Therefore, the molarity of the intravenous glucose solution is 0.30 mol/L.

Answer 2

0.30 mol/L

Step-by-step explanation:

Mass = 108 g

Molar mass of glucose = 180.156 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (108\ g)/(180.156\ g/mol)`

`Moles= 0.5995\ mol`

Given Volume = 2 L

`Molarity=(Moles\ of\ solute)/(Volume\ of\ the\ solution)`

`Molarity=(0.5995)/(2)`

Molarity = 0.3 mol/L