Question

The deepest trench in the world is 11,000 m in depth. Assuming sea water to have a constant density of 1050 kg/m, determine the pressure at this point in atmospheres.

Answer 1

113406825 N/m²

Step-by-step explanation:

The pressure at depth of 11,000 m can be calculated by:

Pressure = Atmospheric pressure + Pressure due to height

Atmospheric pressure = 101325 N/m²

Also,

Where,

is the density of water ()

g is the gravitational acceleration = 9.81 m/s²

h = 11,000 m

Pressure due to height = 113305500 N/m²

Pressure = Atmospheric pressure + Pressure due to height = 101325 N/m² + 113305500 N/m² = 113406825 N/m²

Answer 2

113406825 N/m²

Step-by-step explanation:

The pressure at depth of 11,000 m can be calculated by:

Pressure = Atmospheric pressure + Pressure due to height

Atmospheric pressure = 101325 N/m²

Also,

`P_(height)=\rho* g* h`

Where,

`\rho` is the density of water (
`\rho=1050\ kg/m^3`)

g is the gravitational acceleration = 9.81 m/s²

h = 11,000 m

`P_(height)=1050\ kg/m^3* 9.81\ m/s^2* 11000\ m`

Pressure due to height = 113305500 N/m²

Pressure = Atmospheric pressure + Pressure due to height = 101325 N/m² + 113305500 N/m² = 113406825 N/m²