Question

An electron is released from rest in a uniform electric field of magnitude 2.16 x 10^4 N/C. Calculate the acceleration of the electron. (Ignore gravitation.) Number ______ Units _________

Answer 1

Acceleration of the electron will be
`0.379* 10^(16)m/sec^2`

Step-by-step explanation:

We have given electric field
`E=2.16* 10^4N/C`

Charge on electron
`q=1.6* 10^4C`

So force in the electron
`F=qE=1.6* 10^(-19)* 2.16* 10^(4)=3.456* 10^(-15)N`

Mass of electron
`m=9.11* 10^(-31)kg`

Now according to newton second law

F = ma, here m is mass and a is acceleration

So
`3.456* 10^(-15)=9.11* 10^(-31)a`

`a=0.379* 10^(16)m/sec^2`

So acceleration of the electron will be
`0.379* 10^(16)m/sec^2`