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a laboratory, you determine that the density of a certain solid is 5.23×10−6kg/mm3. Convert this density into kilograms per cubic meter. Notice that the units you are trying to eliminate are now in the denominator. The same principle from the previous parts applies: Pick the conversion factor so that the units cancel. The only change is that now the units you wish to cancel must appear in the numerator of the conversion factor

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Answer:


5.23* 10^(-6)\ kg/mm^3=5230\ kg/m^3

Explanation:

Given : The density of a certain solid is
5.23* 10^(-6) kg/mm³.

To find : Convert this density into kilograms per cubic meter ?

Solution :

We know that,


1\ m^3=10^9\ mm^3

or
10^9\ mm^3=1\ m^3

So,
1 mm^3=(1)/(10^9)\ m^3


1 mm^3=10^(-9)\ m^3

Converting
5.23* 10^(-6) kg/mm³ into kg/m³,


5.23* 10^(-6)\ kg/mm^3=(5.23* 10^(-6))/(10^(-9))\ kg/m^3


5.23* 10^(-6)\ kg/mm^3=5.23* 10^(-6+9)\ kg/m^3


5.23* 10^(-6)\ kg/mm^3=5.23* 10^(3)\ kg/m^3


5.23* 10^(-6)\ kg/mm^3=5230\ kg/m^3

Therefore,
5.23* 10^(-6)\ kg/mm^3=5230\ kg/m^3

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