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A boat crosses a river of width 229 m in which the current has a uniform speed of 0.756 m/s. The pilot maintains a bearing (i.e., the directicon in which the boat points) perpendicular to the river and a throttle setting to give a constant speed of 1.69 m/s relative to the water. What is the magnitude of the speed of the boat relative to a stationary shore observer? Answer in units of m/s. How far downstream from the initial position is the boat when it reaches the opposite shore? Answer in units of m.

2 Answers

5 votes

Final answer:

The speed of the boat relative to a stationary shore observer is found by adding the squared boat and current speeds and taking the square root. The boat's downstream displacement upon reaching the opposite shore is determined by calculating the crossing time using the boat's speed and multiplying by the current speed.

Step-by-step explanation:

The question involves the concept of relative velocity from Physics. To find the magnitude of the speed of the boat relative to a stationary shore observer, we use the Pythagorean theorem. Given that the speed of the boat relative to the water is 1.69 m/s and the speed of the current is 0.756 m/s, the total speed relative to the shore, Vtot, is calculated using Vtot = √(v_boat^2 + v_current^2). Thus, Vtot = √(1.69^2 + 0.756^2) m/s.

To determine how far downstream the boat will be from its initial position upon reaching the other shore, we need to consider the time it takes to cross the river and the velocity of the current. The time to cross is time = width/speed = 229 m / 1.69 m/s, and then the downstream distance is downstream distance = time * current speed.

User Jseb
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6.7k points
3 votes

Answer:

1.85 m/s

102.438 m

Step-by-step explanation:

From vector motion

The resultant velocity


R=√(0.756^2+1.69^2)\\\Rightarrow R=1.85\ m/s

The magnitude of speed of the speed of the boat relative to a stationary shore observer is 1.85 m/s

The distance covered is 229 m

Time = Distance / Speed


\text{Time}=(229)/(1.69)\\\Rightarrow \text{Time}=135.50\ s

Distance = Speed of current × Time

Distance = 0.756×135.5 = 102.438 m

The boat will be 102.438 m from the initial position is the boat when it reaches the opposite shore

User Mahen
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7.2k points