Answer:
The answer (2, 1), (-4,13), (6,-7)
Explanation:
Consider 2x+y=5 as equation 1, and 3y=15-6x as equation 2
1. Substituting values x and y with x=2 and y=1 as given by the coordinates (2,1)
Equation 1
2(2)+1=5 therefor it holds
Equation 2
3(1)=15-(6×2) also holds
2. Substituting values x and y with x=6 and y=-7 as given by the coordinates (6,-7)
Equation 1
2(6)+(-7)=5
5=5 holds
Equation 2
3(-7)=15-(6×6)
-21=-21 also holds
3. Substituting values x and y with x=-4 and y=13 as given by the coordinates (-4,13)
Equation 1
2(-4)+13=13-8=5 holds
Equation 2
3(13)=15-(6×-4)=39 also holds
4. Substituting values x and y with x=-2 and y=-9 as given by the coordinates (-2,-9)
Equation 1
2(-2)+(-9)=-4-9=-13≠5 does not hold
Equation 2
3(-9)≠15-(6×-2)
-27≠27 does not hold
The coordinates (2,1), (-4,13) and (6,-7) can be used as solutions to the system given