Question

hi everybody please who could help me with this question, i am stuck here.. the question is ( solve for x in this equation ( 2sin^2 x - sinx))​

Answer 1

Explanation:

2sin² x - sinx=0

sinx(2sinx - 1 ) = 0

sinx = 0 or 2sinx - 1 = 0

sinx=0 or sinx = 1/2

continue solve in : IR or [0, 2π] ?????