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Nickel (II) oxide reacts with carbon monoxide to form nickel metal. CO(g) + NiO(s) ⇄ CO2(g) + Ni(s) Kp = 20 at 873 K If a reaction vessel at equilibrium contains solid Ni, solid NiO, 400 mm Hg of CO2, and 20 mm Hg of CO, doubling the amount of CO(g) present will lead to the production of more solid nickel at 873 K. Group of answer choices

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Answer:

Step-by-step explanation:

Hello,

Based on the statement of the equilibrium law:


Kp=(P_(CO_2)^(EQ))/(P_(CO)^(EQ))

By increasing (doubling) the amount of carbon monoxide, the production of nickel will increase since its amount is directly proportional with its pressure, so, by adding more reactant (in this case carbon monoxide), the equilibrium is rightward shifted based on Le Châtelier's principle even when solid either reactants or products are not contemplated in the equilibrium law.

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User VedantK
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