Question

What are the solution(s) to the quadratic equation 40 − x2 = 0?

x = ±2Plus or minus 2 StartRoot 10 EndRoot
x = ±4Plus or minus 4 StartRoot 10 EndRoot
x = ±2Plus or minus 2 StartRoot 5 EndRoot
x = ±4Plus or minus 4 StartRoot 5 EndRoot

Answer 1

Answer: The answer is A.x = ±2Plus or minus 2 StartRoot 10 EndRoot

Explanation:

40-x^2=0

x^2=40

x=square root of 40

factor 40

x=square root of 2*2*10

x = 2 StartRoot 10 EndRoot

since its squared

it means that it can either be positive or negative

which is why its A.x = ±2Plus or minus 2 StartRoot 10 EndRoot

Answer 2

`x=+/- 2√(10)`

Explanation:

This equation can be solved directly by isolating the quadratic term in x on one side of the equation (this is because there is no linear term in x n he equation) as follows:

`40-x^2=0\\40=0+x^2\\40=x^2\\x^2=40\\√(x^2) =+/- √(40) \\x=+/-√(4*10) =+/-√(4) *√(10) =+/- 2√(10) \\x=+/- 2√(10)`