Answer:
Minimum value = 7
Q1 = 1/2 (n+1)th term
1/2 (9+1)
1/2 (10)
Q1 = 5th term
Therefore Q1 = 36
Median = 1/2 (n+1)th term
1/2 (19+1)
1/2 (20)
Q2= 10th term
Therefore median (Q2) = 66
Q3 = 1/2 (n+1)th term
1/2 (9+1)
1/2 (10)
Q3 = 5th term
Therefore Q3 = 81
Maximum value = 92