Answer:
76 mmHg
Step-by-step explanation:
The partial pressure of a gas in an ideal gas mixture is the pressure that this gas would exercise if it was alone in the same temperature of the gas mixture.
For the Raoult's law, we can determinate the partial pressure of a gas(Pa) knowing the total pressure (P) and its molar fraction(Xa):
Pa = XaP, so for the oxygen :
Pa = 0.10x760
Pa = 76 mmHg