Question

Two blocks A and B with mA = 2.6 kg and mB = 0.81 kg are connected by a string of negligible mass. They rest on a frictionless horizontal surface. You pull on block A with a horizontal force of 6.5 N. Determine the tension in the string connecting the two blocks.

Answer 1

Step-by-step explanation:

Given

Mass of block A
`(m_a)`=2.6 kg

Mass of block B
`(m_b)`=0.81 kg

Force of 6.5 N is applied on Block A

Force on Block A is F, Tension

thus

`F-T=m_a* a` -----1

where a=acceleration of the system

For Block B

`T=m_b* a` -----2

`F=m_b* a+m_a* a`

`F=\left ( m_a+m_b\right )a`

`F=\left ( 2.6+0.81\right )a`

`a=(6.5)/(3.41)`

`a=1.96 m/s^2`

`T=0.81* 1.96=1.54 N`