Answer:
The vertex is (2, 4), the domain is all real numbers, and the range is y≥ 4
Explanation:
we have
![f(x)=(x-2)^(2)+4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2ztwk549ltdcjhmxmy2tt2i1gmawle7pe1.png)
This is the equation of a vertical parabola in vertex form
![f(x)=a(x-h)^(2)+k](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j87gvl2yolbhqfr2fl6boeum3fkn2t73vx.png)
where
a is a coefficient
(h,k) is the vertex
if a > 0 the parabola open upward and the vertex is a minimum
if a < 0 the parabola open downward and the vertex is a maximum
In this problem we have
a=1
so
the parabola open upward and the vertex is a minimum
The vertex is the point (2,4)
The domain is the interval -----> (-∞,∞)
The domain is all real numbers
The range is the interval ----> [4,∞)
![y\geq 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rbp5s1twovrpcjb06eslkugnrr29lmdzor.png)
The range is all real numbers greater than or equal to 4