Question

As the shuttle bus comes to a sudden stop to avoid hitting a dog, it accelerates uniformly at -4.1 m/s2 as it slows from 9.0 m/s to 0.0 m/s. Find the time interval of acceleration for the bus.

Answer 1

The time interval of acceleration for the bus is 2.20 seconds

Step-by-step explanation:

Acceleration is the rate of change of velocity

→
`a=(v-u)/(t)`

where a is the acceleration, v is the final velocity, u is the initial velocity

and t is the time

The given is:

The uniform acceleration = -4.1 m/s²

The bus slows from 9 m/s to 0 m/s

We need to find the time interval of acceleration for the bus

Lets use the rule above

→ a = -4.1 m/s² , v = 0 m/s , u = 9 m/s

→
`-4.1=(0-9)/(t)`

Multiply both sides by t

→ -4.1 t = -9

Divide both sides by -4.1

∴ t = 2.20 seconds

The time interval of acceleration for the bus is 2.20 seconds