Question

Which expression is even for all integers a and b​

Answer 1

Love i would love to help but where is the question

Explanation:

Answer 2

E) ab + ab

Explanation:

The following options are missing:

A) 2a + b

B) ab + 2a

C) 5a + 6b

D) ab + 2b

E) ab + ab

An expression is even when f(x) = f(-x). In this case, the arguments are a and b. Let's suppose a = 1, b = 1 and analyze every option:

A) 2a + b = 2*1 + 1 ≠ 2*(-1) + (-1)

B) ab + 2a = 1*1 + 2*1 ≠ (-1)*(-1) + 2*(-1)

C) 5a + 6b = 5*1 + 6*1 ≠ 5*(-1) + 6*(-1)

D) ab + 2b = 1*1 + 2*1 ≠ (-1)*(-1) + 2*(-1)

E) ab + ab = 1*1 + 1*1 = (-1)*(-1) + (-1)*(-1) -> this is satisfied for every integers a and b