Question

Use the following cell phone airport data speeds​ (Mbps) from a particular network. Find Upper Q 3. 0.1 0.2 0.2 0.4 0.4 0.4 0.4 0.4 0.5 0.6 0.6 0.6 0.6 0.6 0.8 0.8 0.9 1.1 1.3 1.4 1.5 1.7 1.9 2.2 2.3 2.5 2.6 2.8 3.9 3.9 4.3 4.7 5.4 6.1 7.1 7.9 8.2 9.9 10.6 10.6 11.2 11.7 12.4 13.2 13.2 14.7 14.9 15.5 15.5

Answer 1

9.05

Explanation:

There are 49 numbers in total here. Let's put them in order:

0.1,0.2,0.2,0.4,0.4,0.4,0.4,0.4,0.5,0.6,0.6,0.6,0.6,0.6,0.8,0.8,0.9,1.1,1.3,1.4,1.5,1.7,1.9,2.2,2.3,2.5,2.6,2.8,3.9,3.9,4.3,4.7,5.4,6.1,7.1,7.9,8.2,9.9,10.6,10.6,11.2,11.7,12.4,13.2,13.2,14.7,14.9,15.5,15.5

The Upper Quartile (Q_3) or 3rd quartile is the 75%th mark.

So,

The upper quartile is the (3/4)(n+1)th number, here n is 49, so we get:

`(3)/(4)(n+1)\\=(3)/(4)(49+1)\\=(3)/(4)(50)\\=37.5`

This means the upper quartile is the average of 37th number and 38th number:

(8.2+9.9)/2 = 9.05