Question

Calculate the amount, in moles, of each of the following. You may round atomic masses to one decimal place.

3.29 g CdS =
17.5 g MoO3 =
890 g AlPO4 =

Answer 1

The answer to your question is:

a) 0.023 mol of CdS

b) 0.12 mol of MoO3

c) 7.3 mol of AlPO4

Step-by-step explanation:

a) CdS

MW = 112.4 + 32

= 144 g

144g ------------------ 1 mol

3.28g -------------- x

x = (3.28 x 1) / 144

x = 0.023 mol

b) MoO3

MW = 96 + 3(16) = 144 g

144g ------------------- 1 mol

17.5g ----------------- x

x = (17.5 x 1) / 144

x = 0.12 mol

c) AlPO4

MW = 27 + 31 + 4(16)

MW = 122 g

122 g ------------------ 1mol

890 g ------------------ x

x = (890 x 1) / 122

x = 7.3 mol of AlPO4