Question

Complete and balance the molecular equation for the reaction of aqueous ammonium bromide, NH4Br,

and aqueous lead(II) acetate, Pb(C2H3O2)2. Include physical states.

Answer 1

Molecular equation:

2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq) →2NH₄C₂H₃O₂(aq) + PbBr₂(s)

Step-by-step explanation:

• The molecular equation of the reaction between aqueous ammonium bromide and aqueous lead (ii) acetate is given by;

2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq) →2NH₄C₂H₃O₂(aq) + PbBr₂(s)

• This is an example of a double displacement reaction where two ionic compounds exchange ions with each other to form two new compounds or salts.

• It can also be a precipitation reaction due to the formation of precipitate from two ionic compounds. Lead(ii) bromide is the precipitate formed during the reaction.

• The net ionic equation for the reaction is;

2Br⁻(aq) + Pb²⁺(aq)→ PbBr₂(s)