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The fastest airplane is the Lockheed SR-71. If an SR-71 flies 15.0 km west in 15.3 s, what is its average velocity in kilometers per hour?

User Ronaldtgi
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1 Answer

6 votes

Answer:

3529 km/h west

Step-by-step explanation:

The average velocity is given by:


v=(d)/(t)

where

d is the displacement

t is the time taken

For the plane in this problem, we have:


d=15.0 km


t=15.3 s \cdot (1)/(3600 s/h)=0.00425 h

Therefore, substituting into the formula,


v=(15.0)/(0.00425)=3529 km/h

and the direction is the same as the displacement (west).

User Fred Foo
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