41.3k views
4 votes
Find the equation of the circle: y-intercepts 4 and –8, contain (–12, –8)

User Dor Dadush
by
5.8k points

1 Answer

2 votes

Answer:

(x +6)^2 +(y +2)^2 = 72

Explanation:

The given points are vertices of a right triangle. The circle circumscribing that triangle (through all 3 vertices) will have its center at the midpoint of the hypotenuse:

((0, 4) +(-12, -8))/2 = (-6, -2)

The equation of a circle with center (h, k) through point (a, b) is ...

(x -h)^2 +(y -k)^2 = (a -h)^2 +(b -k)^2

For center (-6, -2) and point (0, 4), the equation is ...

(x +6)^2 +(y +2)^2 = (0+6)^2 +(4 +2)^2

(x +6)^2 +(y +2)^2 = 72

Find the equation of the circle: y-intercepts 4 and –8, contain (–12, –8)-example-1
User Calebm
by
5.9k points