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You are given that a wheel has a radius of 2 feet and a spin rate of 10 revolutions per minute. Describe how you would determine the linear velocity, in feet per minute, of a point on the edge of the wheel.

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Answer:

Linear velocity of point on the edge of wheel having radius of 2 feet and spin rate of 10 revolution per minute is 125.71 feet per minute.

Solution:

Given that radius of wheel = 2 feet

There is a point on edge of the wheel .we need to determine linear velocity of that point.

Let’s first calculate distance covered by a point when 1 revolution of wheel is complete.

When one revolution is complete the distance traveled by a point on edge of the wheel will be equal to circumference of the wheel


=2 \pi \mathrm{r}=2 \mathrm{x}\left((22)/(7)\right) * 2=(88)/(7) \mathrm{feet}

In one revolution, point covers distance of
(88)/(7) feet

So in 10 revolution, point covers distance of
(88)/(7) * 10 = (880)/(7)

Given that in a minute, wheel takes 10 revolution.

Which means in a minute , point covers
(880)/(7) feet that is
(880)/(7) feet per minute = 125.71 feet per minute

Hence linear velocity of point on the edge of wheel having radius of 2 feet and spin rate of 10 revolution per minute is 125.71 feet per minute.

User Pavel Karoukin
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