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Physics question about circular motion​

Physics question about circular motion​-example-1
User Vijayeta
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Answer:

4. A

5. D

Step-by-step explanation:

4) Apply Newton's second law in the radial direction (towards the center):

∑F = ma

T = mv²/r

v = √(Tr/m)

Given T = 30 N, r = 1.5 m, m = 2 kg:

v = √(30 N × 1.5 m / 2 kg)

v = 4.74 m/s

5) Apply Newton's second law to the stopper in the radial direction (towards the center):

∑F = ma

T sin θ = Mv²/(L sin θ)

T = Mv²/(L sin² θ)

User MooGoo
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