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Geometry problem please help me out

m>1=(45 x-30)° , m<5=(20 x+70)°

Geometry problem please help me out m>1=(45 x-30)° , m<5=(20 x+70)°-example-1
Geometry problem please help me out m>1=(45 x-30)° , m<5=(20 x+70)°-example-1
Geometry problem please help me out m>1=(45 x-30)° , m<5=(20 x+70)°-example-2
User Berta
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8.2k points

1 Answer

2 votes

Answer:

see below

Explanation:

Angles 1 and 5 are both outside (not between) the parallel lines, so are "exterior" angles. Angle 1 is on the northwest corner of the intersection; angle 5 is on the southeast corner, so they are not "corresponding." Rather, they are "alternate".

The only answer choice properly describing the angles also properly shows their measure:

Alt Ext ∠s Thm

∠1 ≅ ∠5 = 150°

_____

Since the angles are equal, you can write the equation ...

45x -30 = 20x +70

25x = 100 . . . . . . . . . add 30-20x

x = 4 . . . . . . . . . . . . . divide by 25

We can substitute this value into the expression for angle 5:

20x +70 = 20·4 +70 = 150 . . . . . the angle measures are 150°

Geometry problem please help me out m>1=(45 x-30)° , m<5=(20 x+70)°-example-1
User Gthm
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8.4k points