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1 vote
Solve the inequality.
l2x + 16l > 24

User Natkeeran
by
4.8k points

2 Answers

2 votes

Answer:


\Huge\boxed{\mathsf{X<-20 \quad X>4}}}

Explanation:

Isolate x on one side of the equation.

First, use absolute rule.

2x+16<-24 and 2x+16>24

2x+16<-24

Subtract 16 from both sides.

2x+16-16<-24-16

Solve.

Add the numbers from left to right.

-24-16=-40

2x<-40

Divide by 2 from both sides.

2x/2<-40/2

Solve.

-40/2=-20

X<-20

2x+16>24

Then, subtract 16 from both sides.

2x+16-16>24-16

Solve.

24-16=14

2x>8

Divide by 2 from both sides.

2x/2>8/2

Solve.

8/2=4

X>4

X<-20 & X>4, which is our answer.

User Vmpstr
by
4.7k points
4 votes

Hello Caitlin,

|2x + 16| > 24

We want to solve the absolute value

2x + 16 > 24 or 2x + 26 < -24

So we gonna each of them

2x + 16 > 24

2x > 24 - 16

2x > 8

x > 8/2

x > 4

Now let's solve the second possibility

2x + 26 < -24

2x < -24 - 26

2x < -40

x < -40/2

x < -20

Thus,

The answer is: x > 4 or x < -20

If you have additional question about the answer, please feel free to let me know.

Have a great weekend!

~Alexandrian

User Tuomastik
by
4.8k points