Question

Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h7sh

Answer 1

0.264 g of
`CO_2` can be formed from 288 mg of
`O_2`

Step-by-step explanation:

The balanced chemical equation is

`2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O`

The conversions are

Mass in mg
`O_2` is converted to mass in g
`O_2`

Mass in g
`O_2` is converted to moles
`O_2` by dividing with molar mass

Moles
`O_2` is converted to moles
`CO_2` by using the mole ratio of
`O_2:CO_2` is 9 : 6

Moles
`CO_2` is converted to mass
`CO_2` by multiplying with molar mass
`CO_2`

mass in mg
`O_2` > mass in g
`O_2` >moles
`O_2` > moles
`CO_2` > mass
`CO_2`

`288mg O_2 * ((1g O_2))/((1000mg O_2 )) * \frac {(1molO_2)}{(32gO_2 )}*\frac {(6mol CO_2)}{(9mol O_2 )} * \frac {(44.0 gCO_2)}{(1mol CO_2 )}`

=0.264g (Answer)