Question

A basketball player has a free throw percentage of 92% . What is the probability she misses at least one of his next 27 free throws?

Answer 1

89.5%

Explanation:

The probability of missing at least one of 27 throws is 1 minus the probability of not missing any throws.

P = 1 − (0.92)^27

P ≈ 0.895

There's about a 89.5% probability that the player misses at least one throw out of 27.