Answer:
potential energy = 2.088 ×
J
Step-by-step explanation:
given data
Capacitance C = 1.29 F
voltage V = 56.9 kV = 56.9 × 10³ V
dielectric constant k1 = 425
new dielectric constant k2 = 979
to find out
electric potential energy of the original capacitor when it is charged
solution
we will apply here potential energy of capacitor formula that is
potential energy = 0.5 × C× V² ......................1
here C is Capacitance and V is voltage so potential energy will be from equation 1
potential energy = 0.5 × C× V²
potential energy = 0.5 × 1.29 × (56.9 × 10³)²
potential energy = 2.088 ×
J