Answer:
213 samples needed for 99% confidence interval
Explanation:
We know that:
minimum size of sample needed to be sure about total measurement less than 3.5 degree is given as
![n = [(z_(\alpha/2)* s)/(E)]^2](https://img.qammunity.org/2020/formulas/mathematics/college/lf9cpyep9yy70kk3wscbyqp1iya0s5bu3t.png)
where,
s is standard deviation = 19.8 degree
E IS MARGIN OF ERROR = 3.5 degree
right tail critical value of
Z

so, minimum size of sample needed is
![n = [(2.58* 19.8)/(3.5)]^2](https://img.qammunity.org/2020/formulas/mathematics/college/fo1o88vqrcsqocl4sb6nn8wknpiwzxnvrv.png)
n = 213.02
Therefor 213 samples needed for 99% confidence interval