If you draw the given compound you would see that the longest chain have 8 carbons, so the compound is octone not heptane.
Now you give indices for each carbon atom involved in the principal carbon chain in such a way the substituents are heaving the lowest number.
The correct name of the compound is:
2,4,6,6-tetramethyl-octane
In the attached figure you may see the drawing of the molecule.