Question

Write the point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8. include all your work in your answer.

Answer 1

The point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8 is 8x + y + 62 = 0

Solution:

The point slope form of the line that passes through the points
`\left(x_(1) y_(1)\right)` and parallel to the line with slope “m” is given as

`y-y_(1)=m\left(x-x_(1)\right)` --- eqn 1

Where “m” is the slope of the line.

`x_(1) \text { and } y_(1)` are the points that passes through the line.

From question, given that slope “m” = -8

Given that the line passes through the points (-8,2).Hence we get

`x_(1)=-8 ; y_(1)=2`

By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -8 can be found out.

y-2=-8(x-(-8))

On simplifying we get

y – 2 = -8(x +8)

y – 2 = -8x -64

y – 2 +8x +64 = 0

8x + y +62 = 0

Hence the point slope form of given line is 8x + y +62 = 0