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the perimeter of a childs rectangular sandbox is 18 feet if the length of the sandbox is one foot longer than the width write an equation that can find the length and width of the sandbox

User Sidd Thota
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1 Answer

6 votes

Answer:

Equation:


2(x+(x+1))=18

Width = 4 feet

Length = 5 feet

Explanation:

Let x feet be the width of the rectangle.

If the length of the sandbox is one foot longer than the width, then the length is x + 1 feet.

Use formula


\text{Perimeter}=2(\text{Width}+\text{Length})

The perimeter of a childs rectangular sandbox is 18 feet, thus


18=2(x+(x+1))\\ \\18=2(x+x+1)\\ \\18=2(2x+1)\\ \\9=2x+1\ [\text{Divided by 2}]\\ \\2x+1-1=9-1\\ \\2x=8\\ \\x=4\ feet \\ \\x+1=5 \ feet

User Alex Dovzhanyn
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