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Determine the moment about the origin O of the force F=(13)i + (-12)j + 14(k) that acts at a point A. Assume that the position vector of A is r=2i+3j-4k. The moment about the origin of the force F is ()i+()j+()k

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Answer:


\vec{\tau} = 6\hat{i} + 80\hat{j}+63\hat{k}

Step-by-step explanation:

given,

F=(13)i + (-12)j + 14(k)

position vector of vector A = r = 2 i + 3 j - 4 k

moment of force about origin


\vec{\tau} = \vec{F} * \vec{r}


\vec{\tau} = \begin{bmatrix}\hat{i} &\hat{j}&\hat{j} \\ 13 & -12 &14 \\2& 3 & -4\end{bmatrix}


\vec{\tau} = 6\hat{i} + 80\hat{j}+63\hat{k}

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