Question

Motion at Constant Acceleration: A driver is traveling at 22 m/s (50 mph), notices a stopped car 100 m ahead and then slams on the brakes with a deceleration of 4.0 m/s2. What distance did they travel after they slammed on the brakes and came to a comlplete stop?

Answer 1

60.5 m

Step-by-step explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Equation of motion

`v^2-u^2=2as\\\Rightarrow s=(v^2-u^2)/(2a)\\\Rightarrow s=(0^2-22^2)/(2* -4)\\\Rightarrow s=60.5\ m`

The distance the car will travel after slamming the brakes is 60.5 m

The car is 100-60.5 = 39.5 away from the stationary car