Question

The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2. Compute the wavelength of this line for l H and 21. Note: These are the electronic hydrogen and deuterium atoms, not the muonic forms.]

Answer 1

`\lambda=550\ nm`

Step-by-step explanation:

The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2 i.e.
`n_i=3` and
`n_f=2`

The wavelength of Hi line of the Balmer series is given by :

`(1)/(\lambda)=R((1)/(n_f)-(1)/(n_i))`

`(1)/(\lambda)=1.09* 10^7* ((1)/(2)-(1)/(3))`

`\lambda=5.50* 10^(-7)\ m`

`\lambda=550\ nm`

So, the wavelength for this line is 550 nm. Hence, this is the required solution.