Question

Find the equation of a line passing through (-4,3) and (1,2)

Answer 1

The answer to your question is:

slope y-intercept ( y - 2) = -1/5 (x - 1)

general equation x + 5y - 11 = 0

Explanation:

Data

A (-4, 3)

B (1, 2)

slope = m =
`((y2- y1))/((x2 - x1))`

Process

m =
`((2 - 3))/((1 + 4))`

m =
`(-1)/(5)`

(y - y1) = m(x - x1)

( y - 2) = -1/5(x - 1)

5(y - 2) = -1(x - 1)

5y - 10 = -x + 1

x + 5y - 11 = 0