Answer : The correct option is (d) 2.73 m
Explanation :
By the 2nd equation of motion,

where,
s = distance or height = ?
u = initial velocity = 3.0 m/s
t = time = 0.5 s
a = acceleration due to gravity =

Now put all the given values in the above equation, we get:


Therefore, the correct option is (d) 2.73 m