Question

PLEASE HELP

How to solve radical equations


`√(2x+3) -√(x-2) =2`

Possible Answers:
-11, 0, 2, 3, 5, 8, 11, 16, 100, or no possible solution

Answer 1

3,11

Explanation:

`√(2x+3)=2+√(x-2)\\  squaring\\2x+3=4+x-2+4√(x-2) \\2x+3-4-x+2=4√(x-2) \\x+1=4√(x-2 )\\again~squaring\\x^(2)+2x+1=16(x-2)\\x^(2)+2x-16 x+1+32=0\\x^2-14 x+33=0\\x^2-3x-11x+33=0\\x(x-3)-11(x-3)=0\\(x-3)(x-11)=0\\x=3,11`