Answer:
The system
has a unique solution

Explanation:
We have the system of equations:

To solve this system for Gauss-Jordan method we need the augmented matrix, which is:
![\left[\begin{array}c1&1&7\\3&2&17\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/kzpdnawmivr3e0wao81uj5v29uyfl946l7.png)
Next we need to transform the augmented matrix to the reduced row echelon form via elementary row operations as follows:
- Row Operation 1: add -3 times the 1st row to the 2nd row
![\left[\begin{array}cc1&1&7\\0&-1&-4\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/ezvgeuoozuqdkcnxpg8t73pbwap1jwe7f1.png)
- Row Operation 2: multiply the 2nd row by -1
![\left[\begin{array}cc1&1&7\\0&1&4\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/6dei6mgfnucn6tyoxk5qivbgqiq6rckdzc.png)
- Row Operation 3: add -1 times the 2nd row to the 1st row
![\left[\begin{array}cc1&0&3\\0&1&4\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/azp7b7pyvjdat7vox3mtisstpkvpnzr2ef.png)
From the reduced row echelon form we have the solution of the system
