Answer:
a) Cost
Revenue
![R(x)=0.87x](https://img.qammunity.org/2020/formulas/mathematics/college/3sahek52zc530t2wcy0dnj92ciajw7qltg.png)
Profit
![P(x)=0.7x-350](https://img.qammunity.org/2020/formulas/mathematics/college/6v3cvzhb2l8tfuprcwt6tcbc7rrwpeyl94.png)
b) 500 servings
c) $ 700 dollars
Explanation:
a) The total cost is the cost per serving plus the cost of renting the facility
Cost per serving = 0.17 per serving
Cost of renting = 350
and we write:
![C(x)=0.17x +350](https://img.qammunity.org/2020/formulas/mathematics/college/i45wcly6izsmpu38oxo8u1y5mw63wuo2ac.png)
The total revenue is the what the University charges per serving, which is 87 cents per serving. And we write:
![R(x)=0.87x](https://img.qammunity.org/2020/formulas/mathematics/college/3sahek52zc530t2wcy0dnj92ciajw7qltg.png)
Profit is Revenue minus Cost, which is:
![P(x)= R(x)-C(x)=0.87x-(0.17x +350)= 0.87x -0.17x -350= 0.7x - 350\\\\P(x)=0.7x-350](https://img.qammunity.org/2020/formulas/mathematics/college/j53efecc52ve8atefn6umwxmd369xrei97.png)
b) To break even Revenue equals Cost, we write
![R(x)=C(x)\\0.87x=0.17x+350\\0.87x -0.17x=350\\0.7x=350\\x=(350)/(0.7) =500](https://img.qammunity.org/2020/formulas/mathematics/college/s27pla7s1lsog678v1bpehciqcnu28d8yh.png)
500 servings must the Audubon Society sell to break even.
c) we plug 1,500 into the P(x) equation and we get:
![P(x)=0.7x-350\\P(1,500)=0.7(1,500)-350\\P(1,500)=0.7(1,500)-350\\P(1,500)=1,050-350\\P(1,500)=700](https://img.qammunity.org/2020/formulas/mathematics/college/g9i4joii17x0ozjq5feoxcg6p9xna78let.png)
The sale of 1,500 servings of pasta results in a profit of $ 700 dollars.