Question

Solve the equation x^2-6x-1=0 to the nearest tenth.

Answer 1

9514 1404 393

Answer:

x = {-0.2, 6.2}

Explanation:

The values that go into the quadratic formula are a = 1, b = -6, c = -1.

`x=(-b\pm√(b^2-4ac))/(2a)=(-(-6)\pm√((-6)^2-4(1)(-1)))/(2(1))\\\\=(6\pm√(40))/(2)=3\pm√(10)\\\\\boxed{x\in\{-0.2,\ 6.2\}}`