Question

What is the molarity of .00000093 grams of epinephrine in one liter?

Answer 1

5.076 * 10 ⁻¹² M

Step-by-step explanation:

molarity of a solution is given as -

Molarity (M) = ( w / m ) / V ( in L)

where ,

m = molecular mass ,

w = given mass ,

V = volume of solution ,

From the question ,

w = given mass of epinephrine = 0.00000093 g

V = 1 L

Since , the molecular mass of epinephrine = m = 183,204 g/mol

M = ?

In order to determine the molarity of epinephrine , the above formula is used , by putting the respected values ,

Molarity (M) = ( w / m ) / V ( in L)

M = ( 0.00000093 g / 183,204 g/mol ) / 1 L

M = 5.076 * 10 ⁻¹² M