Answer:
(a)
![X(t)=X(0)+\Delta X*t=5-0.5*t](https://img.qammunity.org/2020/formulas/mathematics/college/g6j85nijg6xkw3khcsf604zbkpmkpeit13.png)
(b)
![X(t)=X(0)+\Delta X*t=1+0.5*t](https://img.qammunity.org/2020/formulas/mathematics/college/mfbmmjcyj7qwtocj772uqqno9x8b77oox6.png)
(c) At 4 weeks, when both will be seeing an average of 3 hours of TV.
Explanation:
a) For the students, they start at X(0)=5 h and ΔX=-0.5 h/week.
We can write
![X(t)=X(0)+\Delta X*t=5-0.5*t](https://img.qammunity.org/2020/formulas/mathematics/college/g6j85nijg6xkw3khcsf604zbkpmkpeit13.png)
b) For the professors, they start at X(0)=1 h and ΔX=+0.5 h/week.
We can write
![X(t)=X(0)+\Delta X*t=1+0.5*t](https://img.qammunity.org/2020/formulas/mathematics/college/mfbmmjcyj7qwtocj772uqqno9x8b77oox6.png)
c) The seew which they will be watching the same amount of hours will be the 4th week.
![X(t)=5-0.5*t=1+0.5*t\\\\5-1=(0.5+0.5)*t\\\\t=4\, weeks](https://img.qammunity.org/2020/formulas/mathematics/college/orpobgaewgs6drl0bjv9idzfultf2llpzw.png)
The amount of hours will be
![x(4)=1+0.5*4=1+2=3\,hours](https://img.qammunity.org/2020/formulas/mathematics/college/2xwvd9uebxlh8dksul8vlej63tjz3ytv1y.png)