Answer:
The distance covered in 2.5 hours is 80100 feet.
Explanation:
The angular speed in radians per second can be obtained as
![\omega =(2\pi N)/(60)rad/sec](https://img.qammunity.org/2020/formulas/mathematics/college/mu2trig5iy4w83gkj6bzddhcuutq294pim.png)
where
N is the revolutions in rpm
Applying the given values we get
![\omega =(2\pi * 170)/(60)=17.8rad/sec](https://img.qammunity.org/2020/formulas/mathematics/college/3j36zmi98d7znvahgnxixjyvlnguyny9i5.png)
Thus the speed of the tire is
![V=r* \omega](https://img.qammunity.org/2020/formulas/mathematics/college/khtdcxrcscg9l288hjnvz0tztzy3lrb5ft.png)
where
r = radius of the tire =15 inches = 0.5 feet in the given case
Applying the given values we get
![V=0.5* 17.8=8.9feet/sec](https://img.qammunity.org/2020/formulas/mathematics/college/tvrl6i7mpi60by1f72ipczzk0opie62fqg.png)
Thus the distance covered in 2.5 hours is
![Distance=Speed* Time\\\\Distance =8.9* 2.5* 3600=80100feet](https://img.qammunity.org/2020/formulas/mathematics/college/ll99bsgwcufbz8uf9mmkm3cm92rvcjz7yv.png)