Answer:
The statement
is a tautology.
![p\rightarrow (q\rightarrow p)\equiv \lnot p\lor (q\rightarrow p) \equiv \lnot p\lor (\lnot q\lor p) \equiv (p\lor \lnot p) \lor \lnot q \equiv T \lor \lnot q \equiv T](https://img.qammunity.org/2020/formulas/mathematics/college/bcdbej69ovrlpjq7wkihv90cswtfr44lw2.png)
Explanation:
We have the following statement:
![p\rightarrow (q\rightarrow p)](https://img.qammunity.org/2020/formulas/mathematics/college/eqsfls056qqq7nwu4e8u23t8zn6evhiwn2.png)
To reduce the statement to a tautology we need to use the table of logical equivalences as follows:
![p\rightarrow (q\rightarrow p)\equiv](https://img.qammunity.org/2020/formulas/mathematics/college/ykneejjt60z8bhy11ruzsqlcic32ufjtb9.png)
by the the logical equivalence involving conditional statement.
by the the logical equivalence involving conditional statement.
by the Associative law.
by the Negation law.
by the Domination law.