Question

a ball rolls start at the top of a hill and rolls down with a velocity of 24m/s after 8s. what is the velocity of the ball?​

Answer 1

`3 m/s^2`

Step-by-step explanation:

I assume you are asking for the acceleration of the ball, not the velocity (in fact, the velocity is already given).

The acceleration is:

`a=(v-u)/(t)`

where in this case we have:

v = 24 m/s is the final velocity

u = 0 is the initial velocity

t = 8 s is the time interval for the velocity to change

Solving the equation,

`a=(24-0)/(8)=3 m/s^2`