Answer:
We conclude that the area of the right triangle is:
![A\:=p^2-2p-3](https://img.qammunity.org/2022/formulas/mathematics/high-school/p12fbfknfvsobg0a0fgzs1o05n8c40z72z.png)
Hence, option A is correct.
Explanation:
From the given right-angled triangle,
Using the formula to determine the area of the right-angled triangle
Area of the right triangle A = 1/2 × Base × Perpendicular
![=(1)/(2)\left(p+1\right)\left(2p-6\right)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ew0i7v1zzbu484auru72415ntdcf8h0h4z.png)
Factor 2p-6: 2(p-3)
Divide the number: 2/2 = 1
![=\left(p+1\right)\left(p-3\right)](https://img.qammunity.org/2022/formulas/mathematics/high-school/wccwa2t5f90c8opmt8vjvfqe8ognav4gul.png)
![\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd](https://img.qammunity.org/2022/formulas/mathematics/high-school/ucg0m1yjkyo3nyh0akowtx8j7svx8cscgh.png)
![=pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)](https://img.qammunity.org/2022/formulas/mathematics/high-school/m74bq9s0nkb5l67ni34sajadz3k08rh2re.png)
![=pp-3p+1\cdot \:p-1\cdot \:3](https://img.qammunity.org/2022/formulas/mathematics/high-school/rjpod5z07hfuu0xnvlsnwrta0ej6qolfbw.png)
![=p^2-2p-3](https://img.qammunity.org/2022/formulas/mathematics/high-school/9xjwqfem7ezqbbnmoc1rvsz6auc1kijadi.png)
Therefore, we conclude that the area of the right triangle is:
![A\:=p^2-2p-3](https://img.qammunity.org/2022/formulas/mathematics/high-school/p12fbfknfvsobg0a0fgzs1o05n8c40z72z.png)
Hence, option A is correct.