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9 votes
9 votes
What is the percent of O in
Cr203?
(Cr = 52.00 amu, O = 16.00 amu)
[?]%

What is the percent of O in Cr203? (Cr = 52.00 amu, O = 16.00 amu) [?]%-example-1
User Michael McGowan
by
2.9k points

1 Answer

14 votes
14 votes

Answer:

31.6%

Step-by-step explanation:

find the molecular formular

(52×2)+(16×3)=152

since the %of oxygen is required

MF of o in Cr2O3 =16×3=48

%O= 48/152×100= 31.6%

User Mikecancook
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3.1k points